Thankfully, yes.
The vector w is represented by by (6, 5)T. The vector v is represented by by (9, 0)T. Find the projection of w onto v. (Find kv and u.)
In the diagram the answer can simply be read off the graph paper. But pretend you didn't notice that.
The result is that u = (6, 0)T + (0, 5)T, as expected. Of course, the example was easy.
Was it actually necessary to compute | w |?