No.
Here is a program that uses the static void sort( int[] )
method of Arrays.
The method is static so it can be used without constructing an Arrays object.
import java.util.Arrays;
class ArrayDemoOne
{
public static void main ( String[] args )
{
int[] scramble = {148, -23, 67, 110, -17, 44, 103, -12, -8, 91, -12, 43, 0, 9, 80, 34, 21, 44, 15, 11};
System.out.print("Scrambled array: ");
for ( int j=0; j < scramble.length; j++ )
System.out.print( scramble[j] + " ");
System.out.println();
Arrays.sort( scramble );
System.out.print("Sorted array: ");
for ( int j=0; j < scramble.length; j++ )
System.out.print( scramble[j] + " ");
System.out.println();
}
}
The output of the program is:
Scrambled array: 148 -23 67 110 -17 44 103 -12 -8 91 -12 43 0 9 80 34 21 44 15 11 Sorted array: -23 -17 -12 -12 -8 0 9 11 15 21 34 43 44 44 67 80 91 103 110 148
Could compareTo() be used to decide on the order for
an array of String references?