No. Each j is local to its own method.
They are different local variables.
Here is the program (yet again!) with a slight mistake. Can you find the mistake?
The mistake is a syntax error. The compiler will find it right away and not compile the program.
// Array Example
//
class ChangeArray
{
public void print ( int[] x )
{
for ( int j=0; j < x.length; j++ )
System.out.print( x[j] + " " );
System.out.println( );
}
public void zeroElt ( int[] x, int elt )
{
if ( elt < x.length )
x[ elt ] = 0;
}
// Make all the elements zero.
public void zeroAll ( int[] ar )
{
for ( j=0; j < ar.length; j++ )
ar[j] = 0;
}
}
public class ChangeTest
{
public static void main ( String[] args )
{
ChangeArray cng = new ChangeArray();
int[] value = {27, 19, 34, 5, 12} ;
System.out.println( "Before:" );
cng.print( value );
cng.zeroAll( value );
System.out.println( "After:" );
cng.print( value );
}
}
Where is the mistake?