What does the following code write to the monitor?
#include <stdio.h> int funct( int a, int b ) { int c=3 ; printf("scope f: a=%d b=%d c=%d\n", a, b, c ); } int main ( void ) { int a=77, b=99; funct( 1, 2 ); printf("scope m: a=%d b=%d\n", a, b ); system("pause") ; /* Remove if not needed */ return 0 ; }
The two parameters a
and b
are defined in the parameter
list of the function, and so have block scope for the block of that function.
(Such a block is sometimes called a function body.)
The parameters are assigned values 1 and 2 when main()
calls the
function.