[E-1]Write a function that determines if a character
is one of the upper case characters 'A' through 'Z'. If so, return 1, otherwise
return zero. Here is a prototype for the function:
int isUppercase( int ch );
The argument for the function is of type int.
The eight bits of the character itself will be in the low order byte
of the argument.
Here is a skeleton of a testing program Finish it by completing the function. With a programming environment (such as Bloodshed Dev-C++) use copy-and-paste to copy this code into the editor window and then save it to a source file.
/* Puzzle S01 -- detect upper case characters */
#include <stdio.h>
#include <stdlib.h>
int isUppercase( int ch )
{
. . . .
}
int main()
{
int trials[] = {'a', 'B', 'Z', ' ', '+', 'z', 'Z', 0x33 };
int j, ch;
for ( j=0; j<sizeof(trials)/sizeof(int); j++ )
{
ch = trials[j];
if ( isUppercase( ch ) )
printf("%c is upper case\n", ch);
else
printf("%c is NOT upper case\n", ch);
}
return 0;
}
Note: this function is similar to the function isupper()
described in <ctype.h>. In professional-level code,
use the standard function rather than your own.