a=77 *pa=77
#include <stdio.h>
int main( void )
{
int a = 77;
int *pa = &a ;
printf("a=%d *pa=%d\n", a, *pa );
return 0;
}
Comments:
In the printf statement, the expression *pa means to follow the
pointer in pa and use what is there (the variable a) in this case.