Answer DB14

/* Puzzle D14 -- compute the sum (a[j]-b[j])**2
                 for elements in two arrays of doubles */


double squareDiffArray( int size, double a[], double b[] )
{
  int j;
  double diff, sum = 0;
  
  for ( j=0; j < size; j++ )
  {
    diff=a[j]-b[j];
    sum += diff*diff;
  }
    
  return sum;
}