```11  1 11                                       1 1  1 11
0110 1110         0000 0000 0000 0000 0000 0000 0110 1110
1100 0110         0000 0000 0000 0000 0000 0000 1100 0110
—————————         ———————————————————————————————————————
0011 0100         0000 0000 0000 0000 0000 0001 0011 0100
```

# All Arithmetic is 32-bits

MIPS has no instructions for eight-bit arithmetic. Say that there were two operands in the low order bytes of two registers (as above). A fullword addition of these registers puts the same results in the low-order byte that an 8-bit addition would. However, the carry out of the high-order bit of the eight bits becomes bit 8 of the 32-bit result. Further bit manipulation instructions can be used to deal with it.

So there is no need for eight-bit arithmetic instructions, nor for halfword arithmetic instructions.

### QUESTION 9:

Now divide the sum we just calculated by two. Do this by shifting right one place:

``` 0011 0100         0000 0000 0000 0000 0000 0001 0011 0100
```