lui $13, 0x0004 lw $12, 0x10($13)
$13 contains 0x00040000.
To get to the address we need,
use an offset of 0x10.
the base register
can be loaded with multiples
But often you want a more specific address in the base register.
to fill the bottom 16 bits.
to 32 bits then does a bitwise OR of that with the contents of register
The result goes into register
memory is as above.
instruction (below) loads the word
at 0x0060500C into
Complete the instruction sequence so that the base register contains the address
which will be used with a displacement of