```
1111 1111 1111 0000 → 0011 1111 1111 1100
```

Is the resulting pattern the correct representation for -16/4? No. The result represents a large positive number, not -4

A right shift logical can not be used to divide a negative integer by two.
The problem is that a shift right logical moves zeros into
the high order bit.
This is desirable in some situations,
but not for dividing negative integers
where the high order bit is the "sign bit."
An **arithmetic** right shift replicates the sign bit
as needed to fill bit positions.

The "sign bit" is the high order bit of the pattern. It can be a zero or a one. Whatever it is, it is replicated as needed to fill the positions that have been moved to the right.

Of course, on MIPS, the full 32-bit pattern in a register is shifted and the sign bit is bit 31 of that pattern.

Is there a need for an *arithmetic shift left* instruction?