Answer:

0000 1111 1010 0101           0FA5 
0011 0110 1000 1111           368F 
-------------------           ----
0011 1111 1010 1111           3FAF

Running the Program

Doing the problem by hand yields the result, 0x3faf. Of course, when the program runs the result will be 32 bits long: 0x00003faf. To run the program:

Create a source file.
Start SPIM.
Load the source file.
Set simulator switches (only the following matter at this time):
- ON — general registers in hexadecimal.
- ON — bare machine.
- OFF — allow pseudo instructions.
- OFF — load trap file.
Push F10 once per instruction.

The picture shows the result of running the program. The result in $10 is what was expected.

QUESTION 7:

Here is the complete line for the first instruction from the source window:

[0x00400000]    0x34080fa5    ori  $8, $0, 4005       ori  $8,$0,0x0FA5

Look at the 32-bit machine instruction at address 0x00400000. Do you see the immediate operand in it?