After the instruction
executes, what is in
The 16-bit 0x2
immediate operand has been zero-extended and copied into register
the OR operation was done with the zeros in register
the result was a copy of the zero-extended immediate operand.
Copying a bit pattern into a register is usually called
loading the register.
$8 was loaded with
a 32-bit pattern.
The pattern could represent a positive two.
If so, register
$8 was loaded with positive two.
Here is a description of the
ori instruction when used
to load a register:
ori d,$0,const # register d <--
constis 16-bits, so # 0x0000 ...
const represents an integer,
then 0 ≤
const ≤ 65535.
The three operands of the assembly instruction
must appear in that order.
Can the immediate operand
ori be regarded as a signed integer?