What is sixteen times 8B3 ?
Adding a 0 to the end of an integer written in base sixteen multiplies the integer by sixteen. To multiply an integer by sixteenN, add N zeros on the right:
8B3 × 103 = 8B3000 (Here 10 means sixteen.)
To divide an integer represented in hexadecimal by 16, remove the rightmost digit. The result is the quotient. The removed digit is the remainder.
8B3 div sixteen = 8B (remainder 3).