What is sixteen times 8B3 ?

8B30

Adding
a 0 to the end of an integer written in base sixteen multiplies
the integer by sixteen.
To multiply an integer by sixteen^{N}, add N zeros on the right:

8B3 × 10^{3}= 8B3000 (Here 10 means sixteen.)

To divide an integer represented in hexadecimal by 16, remove the rightmost digit. The result is the quotient. The removed digit is the remainder.

8B3 div sixteen = 8B (remainder 3).